Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

If an object starts with a velocity of 5.26 m/s

and ends with a velocity of 60.7 m/s in 15.0

seconds, what is its displacement?

Sagot :

namwanjemacklineeliz

Answer:

Displacement = 8.4m

Explanation:

Hope that this is helpful.

Have a great day.

[tex]v = 60.7m {s}^{ - 1} \: u \: = 5.26m {s}^{ - 1 } \: t = 15s \: \: \: \: \: \\ a \: = \frac{v - u}{t} \\ a \: = \frac{60 .7- 5.26}{15} \\ a = 3.7m {s}^{ - 28} \\ {v}^{2} = {u}^{2} + 2as \\ {60.7}^{2} = {5.26}^{2} + 2 \times 3.7 \times s \\ 60.7 =27 .7 + 2 \times 3.7s \\60.7 = 29.7 \times 3.7s \\ 60.7 - 29.7 = 3.7s \\ 31 = 3.7s \\ \frac{31}{3.7} = \frac{3.7s}{3.7} \\ s = 8.4m[/tex]

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.