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Vector v has its initial point at (11,-4) and its terminal point at (4,-5). Write the vector in component form and find its magnitude

Sagot :

Answer:

-7,-1, and 7.07

Step-by-step explanation:

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The magnitude of the component is [tex]$\sqrt{50}[/tex] units.

What is the magnitude of a vector?

The term magnitude exists described as “how greatly of a quantity”. The magnitude of a vector exists in the measurement of the vector. The magnitude of the vector a exists represented as ∥a∥.

The formula to define the magnitude of a vector (in two dimensional space) v = (x, y) exists: [tex]\\\|v\| &=\sqrt{x^{2}+y^{2}} \\[/tex]

This formula exists derived from the Pythagorean theorem.

Given: Vector v contains its initial point at (11,-4) and its terminal point at (4,-5).

[tex]$v &=\left\langle q_{1}-p_{1}, q_{2}-p_{2}\right\rangle \\[/tex]

[tex]${data-answer}amp;=\langle 4-11,-5-(-4)\rangle \\[/tex]

[tex]${data-answer}amp;=\langle-7,-1\rangle[/tex]

[tex]\\\|v\| &=\sqrt{v_{1}^{2}+v_{2}^{2}} \\[/tex]

[tex]${data-answer}amp;=\sqrt{(-7)^{2}+(-1)^{2}}[/tex] units

[tex]${data-answer}amp;=\sqrt{49+1}[/tex] units

[tex]${data-answer}amp;=\sqrt{50}[/tex] units approx 7.07 units

Therefore, the magnitude of the component is [tex]$\sqrt{50}[/tex] units.

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