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How many joules of energy are required to melt 423g of water at 0°C?

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Explanation:42. Practice Problem  How many joules of energy are required to vaporize 423g of water at 100oC and 1atmosphere of pressure. q = mHv m = 423 g Hv = 2260 J/gq = (423g) (2260J/g) = 955,980 J = 956 43. Table T – Heat Formulas

The amount of heat needed to melt 423 g of water at 0°C is 141282 J

The heat required to melt water can be obtained by using the following formula:

Q = mL

Q is the heat required.

L is the latent heat of fusion (334 J/g)

m is the mass.

With the above formula, we can obtain the heat required to melt the water as illustrated below:

Mass of water (m) = 423 g

Latent heat of fusion (L) = 334 J/g

Heat (Q) required =?

Q = mL

Q = 423 × 334

Q = 141282 J

Therefore, the amount of heat needed to melt 423 g of water at 0°C is 141282 J

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