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In a friendly soccer game, you hit a ball with a speed of 13 m/s at an angle of 24 degrees above the horizontal. (A) How long does it take for the ball to reach the goal if it is 4.2 meters away? (B) How high is the ball when it reaches the goal?

Sagot :

a) V= 13m/s at 24 degrees

X component of velocity Vx= V*cos24 =11.876 m/s

distance =4.2 meter

time =distance/speed =4.2/11.876 =0.3537 s

b) Vertical component of speed = Vy=vsin24=

5.29 m/s

s=ut+0.5at^2 =5.29880.3537-0.5*9.8*0.3537^2

=1.257 m above ground

Hope I helped! ヾ(^▽^*)))

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