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Sagot :
The values of the letters in coordinates (a, b) and (c,d) are;
a = -4
b = -6
c = 2
d = 6
We are given two equations;
-6x + 3y = 6 ---(eq 1)
x² + y = 10 ---(eq 2)
- We are told that they intersect at coordinates; (a, b) and (c, d).
Let us make y the subject in eq 2 to get;
y = 10 - x² --(eq 3)
- Let us put 10 - x² into eq 1 to get;
-6x + 3(10 - x²) = 6
expanding further gives;
-6x + 30 - 3x² = 6
rearranging gives;
3x² + 6x - 24 = 0
Using online quadratic equation solver, we have;
x = -4 and x = 2
Putting x = -4 into eq 3 gives;
y = 10 - (-4)²
y = 10 - 16
y = -6
Putting x = 2 into eq 3 gives;
y = 10 - (2)²
y = 10 - 4
y = 6
- Thus, the coordinates are; (-4, -6) and (2, 6)
Comparing with (a, b) and (c,d), we have;
a = -4
b = -6
c = 2
d = 6
Read more at; https://brainly.com/question/15165519
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