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Sagot :
Answer: A) 3.5 mol/L
Explanation:
To determine the molarity, we have to find the number of moles in the volume given, and then extrapolate to find the number of moles that would be in 1 L.
Determine the moles in the given volume
moles of LiCl = mass ÷ molar mass
= 139.9 g ÷ 42.39 g/mol
= 3.30 mol
Find the moles in 1 L
Since 930 mL of LiCl = 3.30 mol
then 1000 mL of LiCl = (3.30 mol × 1000 mL/L) ÷ 930 mL
= 3.55 mol/L
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