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An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the floor of the elevator on a(n) 62 kg passenger? answer in units of n.

Sagot :

clotildes

Answer:

Explanation:

Fr= Fn-P

ma=Fn-mg

Fn= m(a+g)

Fn=62(1.2+9.8)

Fn= 682N

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