Answered

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solve for x.

- 6 ≥ 10 - 8 x

Sagot :

rlesandisusanya

Answer:

[tex]x \geqslant 2 \: \: \: \: or \: \: \: \: 2 \leqslant x \\ [/tex]

Step-by-step explanation:

[tex] - 6 \geqslant 10 - 8x \\ - 6 - 10 \geqslant - 8x \\ - 16x \geqslant - 8x \\ \frac{ - 16}{ - 8} \leqslant x \\ 2 \leqslant x[/tex]

aayu0302

Answer:

x ≥ 2

Step-by-step explanation:

-6 ≥ 10 - 8x

=> 8x - 6 ≥

=> 8x ≥ 10 + 6

=> 8x ≥ 16

=> x ≥ 16/8

=> x ≥ 2

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