Weeniedog21
Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Two skaters face one another and stand motionless, then push against each other on the ice. If one's mass is 55 kg and he moves to the left after the push at a velocity of 4.3 m/s, how fast was the other skater traveling after the push if her mass was 48 kg.​

Sagot :

Trancescient

4.9 m/s to the right

Explanation:

We are going to use the conservation law of linear momentum to find her velocity. Initially, they are motionless so their initial total momentum is zero. Let's assume that anything moving to the left has a negative velocity and anything moving to the right has a positive velocity. We can write the conservation law of momentum as

[tex]0 = M_mv_m + M_wv_w[/tex]

where

[tex]M_m[/tex] = mass of the man = 55 kg

[tex]v_m[/tex] = velocity of the man = -4.3 m/s

[tex]M_m[/tex] = mass of the woman = 48 kg

[tex]v_w[/tex] = velocity of the woman

[tex]\Rightarrow 0 = (55\:\text{kg})(-4.3\:\text{m/s}) + (48\:\text{kg})v_w[/tex]

Solving for [tex]v_w,[/tex]

[tex]v_w = \left(\dfrac{55\:\text{kg}}{48\:\text{kg}}\right)(4.3\:\text{m/s}) = 4.9\:\text{m/s}[/tex]

going to the right.

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.