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If a fair coin is tossed twice the possible outcomes are HH, HT, TH or TT, where HH means both tosses are heads and HT means that the first toss is a head and the second toss is a tail, etc. Since the coin is fair, a 50-50 chance of getting a head or a tail, we assign a probability of 1/4 to each of the four outcomes. Assuming that a fair coin was tossed twice, find the probability that both tosses were heads given that at least one of the tosses was a head. Round your answer to 4 decimal places.

Sagot :

fichoh

The conditional probability value rounded to 4 decimal places is : 0.2500

The relation can be used to find the conditional probability of events given :

P(HH | Atleast 1 head) = P(HHn(Atleast 1 H)) / P(Atleast 1 H)

P(Atleast 1 H) = P(HT + TH + HH)

P(Atleast 1 H) = P(HT + TH + HH) = 3(0.25) = 0.75

P(HHn(Atleast 1 H)) = P(HH) × P(Atleast 1 H) = 0.25 × 0.75 = 0.1875

Therefore, the conditional probability can be expressed as :

  • P(HH | Atleast 1 head) = 0.1875 / 0.75 = 0.25

Therefore, P(HH | Atleast 1 head) is 0.25

Learn more : https://brainly.com/question/18153040

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