Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

suppose the blocks collide elastically. picking the positive direction to the right, what is the velocity of the bigger block after the collision takes place?

Sagot :

okpalawalter8

We have that with v_1 =v this goes to show that  the velocity of the bigger block after the collision takes place is v

From the question we are told

Suppose the blocks collide elastically. picking the positive direction to the right, what is the velocity of the bigger block after the collision takes place?

Generally the equation for Momentum   is mathematically given as

P=mv

Therefore

[tex]m_1v_2=m_2v_2[/tex]

Hence

[tex]v_1=\frac{m_2v_2}{m_1}[/tex]

Therefore

[tex]v_1=\frac{mv_2}{2m}\\\\v_1=\frac{v_2}{2}[/tex]

Hence

[tex]2v+v=v_1+v_2\\\\v_1=v[/tex]

Now

with v_1 =v this goes to show that  the velocity of the bigger block after the collision takes place is v

For more information on this visit

https://brainly.com/question/21811998

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.