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suppose the blocks collide elastically. picking the positive direction to the right, what is the velocity of the bigger block after the collision takes place?

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okpalawalter8

We have that with v_1 =v this goes to show that  the velocity of the bigger block after the collision takes place is v

From the question we are told

Suppose the blocks collide elastically. picking the positive direction to the right, what is the velocity of the bigger block after the collision takes place?

Generally the equation for Momentum   is mathematically given as

P=mv

Therefore

[tex]m_1v_2=m_2v_2[/tex]

Hence

[tex]v_1=\frac{m_2v_2}{m_1}[/tex]

Therefore

[tex]v_1=\frac{mv_2}{2m}\\\\v_1=\frac{v_2}{2}[/tex]

Hence

[tex]2v+v=v_1+v_2\\\\v_1=v[/tex]

Now

with v_1 =v this goes to show that  the velocity of the bigger block after the collision takes place is v

For more information on this visit

https://brainly.com/question/21811998

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