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how to solve 1.2x+1.4y=2.7 and 0.4x-0.3y=0.9 in substitution

Sagot :

clareeee

Answer:

x=0.8712, y=1.1818

Step-by-step explanation:

1.2x+1.4y=2.7 --(1)

0.4x-0.3y=0.9--(2)

1.2x=2.7-1.4y

x=(2.7-1.4y) / 1.2 --(3)

substitute (3) in (2)

[tex]0.4(2.7-1.4y) / 1.2 -0.3y=0.9[/tex]

[tex](1.8 - 0.56y) \frac{1}{3} - 0.3y = 0.9[/tex]

times both sides with 1/3

[tex] \frac{1}{3} (1.08 - 0.56y( \frac{1}{3} ) - 0.3y = 0.9)[/tex]

1.08-0.3=0.56y+0.1y

0.78=0.66y

y=1.1818

substitute y in (3)

x=2.7-1.4(1.1818) /1.2

x=0.8712

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