Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

The ages of three brothers are consecutive, even integers. If the sum of the first even integer, three times the second even integer and twice the third even integer is fifty. Find the ages of all three brothers

Sagot :

Answer:

The ages of all three brothers are 4,6,8 years.

Step-by-step explanation:

Here n is the smallest of the three consecutive even integers, the condition gives you this equation

2n + 3*(n+2) + (n+4) = 34.

2n + 3n + 6 + n + 4 = 34

6n = 24

n = 4.

Answer. The ages are 4, 6 and 8 years.

Hope this helps you.

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.