Answered

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A little confused here!

Hey guys. I just need someone's help to clarify things with me.

As I was doing the equations, I got to:

x^-1
-----
x^13

I moved the x^-1 down to x^13 so they'd subtract. But when I did, x^-1 became positive.

So it became x^13 times x^1

Radical Rule: a^n x a^m is pretty much a^n+m

So my answer was 14.

How did x^-1 become positive in this case?

A Little Confused Here Hey Guys I Just Need Someones Help To Clarify Things With Me As I Was Doing The Equations I Got To X1 X13 I Moved The X1 Down To X13 So T class=

Sagot :

djtwinx017

Step-by-step explanation:

Given [tex]\frac{x*x^{-2} }{x^{13}}[/tex]

= [tex]\frac{x*x^{-2} }{x^{13}} = \frac{x^{-1} }{x^{13}}[/tex]

According to the Negative Exponent Rule, [tex]a^{-n} = \frac{1}{a^{n}}[/tex]

Therefore, [tex]\frac{x^{-1} }{x^{13}} = \frac{1}{x^{1}*x^{13}} = \frac{1}{x^{13+1}}= \frac{1}{x^{14}}[/tex]

In other words,  [tex]x^{-1}[/tex] became positive because of the Negative Exponent Rule. Once you bring [tex]x^{-1}[/tex] down towards the denominator, you're essentially removing its negativity and turning its exponent into a positive value. Once that takes place, then you could apply the Product Rule of Exponents onto the exponents in the denominator, where it states, [tex]a^{m}a^{n} = a^{m+n}[/tex].

Please mark my answers as the Brainliest if you find my explanations helpful :)

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