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If a 70 kg. skater acted upon by an unbalanced force of 161 N [West], what is
its acceleration?


Sagot :

According to Newtonʼs Second Law of Motion:

F net = m  x  a

or

a = F net / m

Acceleration = net Force/ Mass = 161 / 70 = 2.3 m/s^2  [W]

If a 70 kg skater is acted upon by an unbalanced force of 161 N [West], his acceleration would be 2.30  m/s² towards the west

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = m*a

where F represents the force applied

m is the mass of the object

a is the acceleration of the object

As given in the problem If a 70 kg. skater acted upon by an unbalanced force of 161 N

F =ma

By substituting the values of the force and the mass as 161 N and 70 kg respectively

161 N = 70×a

a= 2.30 m/s²

Thus, If a 70 kg skater is acted upon by an unbalanced force of 161 N, his acceleration would be 2.30  m/s² towards the west

Learn more about Newton's second law, here

brainly.com/question/13447525

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