Answered

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Write x2 + 6x +13 in the form (x + a)

2 + b where a and b are integers.

Sagot :

discipulus

Step-by-step explanation:

a and b are not integers

[tex] {x}^{2} + 6x + 13 = 0 \\ x = - 3 \pm2i[/tex]

[tex]a \: \in \mathbb{C}[/tex]

[tex]b \: \in \mathbb{C}[/tex]

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