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Solve 4a = 20
solve 3y + 9 = 24
solve y/3 - 5 = 4
solve 3=9 - 4k
solve 6w=4w=9
solve 3x + 8 = 2

please answer with an explanation
60 points given

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏx

Here's the solutions :

1. solve for a :

  • [tex]4a = 20[/tex]

  • [tex]a = \dfrac{20}{4} [/tex]

  • [tex]a = 5[/tex]

2. solve for y :

  • [tex]3y + 9 = 24[/tex]

  • [tex]3y = 24 - 9[/tex]

  • [tex]3y = 15[/tex]

  • [tex]y = \dfrac{15}{3} [/tex]

  • [tex]y = 5[/tex]

3. solve for y :

  • [tex] \dfrac{y}{3} - 5 = 4[/tex]

  • [tex] \dfrac{y}{3} = 5 + 4[/tex]

  • [tex] \dfrac{y}{3} = 9[/tex]

  • [tex]y = 9 \times 3[/tex]

  • [tex]y = 27[/tex]

4. solve for k :

  • [tex]3 = 9 - 4k[/tex]

  • [tex]3 - 9 = -4 k[/tex]

  • [tex] - 6 = - 4 k[/tex]

  • [tex]k = \dfrac{ - 6}{ - 4} [/tex]

  • [tex]k = \dfrac{3}{2} \: \: \: or \: \: 1.5[/tex]

5. there's something wrong with this question.

6. solve for x :

  • [tex]3x + 8 = 2[/tex]

  • [tex]3x = 2 - 8[/tex]

  • [tex]3x = - 6[/tex]

  • [tex]x = \dfrac{ - 6}{3} [/tex]

  • [tex]x = - 2[/tex]

i hope it helped...

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