TRUEBOSS72
Answered

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Please help me with the following question below:

Please Help Me With The Following Question Below class=

Sagot :

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Molarity as Stoikiometri

  • Level : SHS

Equatuions od Molarity :

M = m/Mr × 1000/V

Mr Lithium Dichromate (Li2CrO4)

= Ar Li (2) + Ar Cr + Ar O (4)

= 7 (2) + 52 + 16 (4)

= 14 + 52 + 64

= 130 g/mol

Molarity

= m/Mr × 1000/V

= 19.5 g/130 g/mol × 1000/95 mL

= 0.15 mol × 10.53 /L

= 1.5795 mol/L

So, the molarity of the solution is 1.5795 mol/L

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