Answered

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A house that was heated by electric resistance heaters consumed 1500 kWh of electric
energy in a winter month. If this house were heated instead by a heat pump that has an
average COP of 2.5, determine how much money the homeowner would have saved
that month. Assume a price of Tk 6/kWh for electricity.

Sagot :

Answer:

2.5=1500/Whp=> Whp=600 kWh

delWgain=1500-600=900 kWh

Money saved= 900* 6tk*=5400 tk

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