davistomekia28
Answered

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What is the solution to the system -3×+4y+2z=-3 2×-4y-z=0 y=3x-13

Sagot :

Answer:

x=5, y=2, z=2

Step-by-step explanation:

y=3x-13

-3x+4y+2z = -3x + 4(3x-13) + 2z = 9x+2z-52 = -3

9x + 2z = 49  ... (1)

2x-4y-z = 2x-4(3x-13)-z = -10x-z+52 = 0

10x + z = 52  ... (2)

(2)*2-(1): 11x = 55         x = 5

y = 3x-13 = 15-13 = 2      y=2

z = (49-9x) / 2 = 2         z = 2

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