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Sagot :
A score of 115 is one standard deviation above the mean according the normal distribution principle.
Given the Parameters :
Average score or mean = 100
Standard deviation = 15
An IQ score, X = 115 can be related to the mean and standard deviation of the IQ score distribution thus :
- Mean + number of standard deviations = Score
- 100 + 15 = 115 ;
This means that a score of 115 is one standard deviation above the mean score.
Therefore, a score of 115 is one standard deviation above the mean score of 100
Learn more :https://brainly.com/question/8165716
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