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find three consecutive even integers whose sum 72

Sagot :

Anonimity

22, 24, 26

Step-by-step explanation:

2n - 2 + 2n + 2n + 2 = 72

6n = 72

n = 72/6

n = 12

∴ so three consecutive even integers whose sum is 72 :

2n - 2

= 2(12) - 2

= 24 - 2

= 22

2n

= 2(12)

= 24

2n + 2

= 2(12) + 2

= 24 + 2

= 26

verification

22 + 24 + 26

= 46 + 26

= 72 ✓✓

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