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Si la fuerza de repulsión entre dos cargas es 18 × 1013

Si La Fuerza De Repulsión Entre Dos Cargas Es 18 1013 class=

Sagot :

Answer:

Explanation:

F = kQq/r²

r = √(kQq/F)

a)  r = √(8.899(10⁹)(8)(4) / 18(10¹³)) = 0.0397749... m

  r = 40 mm

b) r = √(8.899(10⁹)(12)(3) / 18(10¹³)) = 0.0421876... m

   r = 42 mm

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