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Find two consecutive even integers such
that 5 times the smaller integer is 44 more
than 2 times the larger integer.

Sagot :

Step-by-step explanation:

5n = 44 + 2(n+2)

5n = 44 +2n+4

5n-2n = 48

3n = 48

n = 16

the integers are : 16 and 18

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