25midowning
Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

I have the equation.
16x^0+2x^2*y^-1
How do I solve the equation if x = 2 and y = 4?

Sagot :

Selena328

Answer:

18

Step-by-step explanation:

[tex] \\ \sf16 {x}^{0} + 2 {x}^{2} \times {y}^{ - 1} [/tex]

Now putting the values of x and y.

[tex] \\ \sf16 \times {2}^{0} + 2 \times {2}^{2} \times {4}^{ - 1} [/tex]

[tex] \\ \sf = 16 \times 1 + 2 \times 4 \times \frac{1}{ {4}}[/tex]

[tex] \\ \sf = 16 + 2[/tex]

[tex] \\ \sf = 18[/tex]

Note:

•If the power of a number is 0 then it's value will be 1.

•If the power of a number is negative then reciprocal the number to make the power positive.

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.