Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

What is the equation of a line that passes trough (6,-1) and is parallel to the line that has a slope of -2/3?

Sagot :

Justin975

Answer:

y=-2/3x+3

Step-by-step explanation:

First, identify the slope you need for your equation. The keyword here is "parallel" so the slope you need is the same as the given slope (-2/3).

Next, use the ordered pair (6,-1); it's on the line that you need to find the equation for. Using slope-intercept form (y=mx+b), plug the -1 in for y, plug the 6 in for x, and plug in your slope of -2/3 for m. Solve for b, your y-intercept. You should get 3.

You have your slope and y-intercept now. Create your equation:

y=-2/3x+3.

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.