Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

What is the equation of a line that passes trough (6,-1) and is parallel to the line that has a slope of -2/3?

Sagot :

Justin975

Answer:

y=-2/3x+3

Step-by-step explanation:

First, identify the slope you need for your equation. The keyword here is "parallel" so the slope you need is the same as the given slope (-2/3).

Next, use the ordered pair (6,-1); it's on the line that you need to find the equation for. Using slope-intercept form (y=mx+b), plug the -1 in for y, plug the 6 in for x, and plug in your slope of -2/3 for m. Solve for b, your y-intercept. You should get 3.

You have your slope and y-intercept now. Create your equation:

y=-2/3x+3.

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.