lephamminhphuong1131
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What is an equation of the line that passes through th (3,-1) and has a slope of 2?​

Sagot :

VirαtKσhli

The given point to us is (3,-1) and the slope of the line is 2 . We can use the point slope form of the line as ,

[tex]\sf\longrightarrow m ( x - x_1) = y - y_1[/tex]

Substitute the values ,

[tex]\sf\longrightarrow 2( x - 3 ) = y - (-1) [/tex]

Simplify LHS and RHS ,

[tex]\sf\longrightarrow 2x - 6 = y +1 [/tex]

Put all terms on one side ,

[tex]\sf\longrightarrow \boxed{\bf 2x - y -7=0} [/tex]

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