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A student writes the equation for a line that has a slope of -6 and passes through the point (2, –8).

y -(-8) = -6(x - 2)

y -(-8) = -6x + 12

y -(-8) + 8 = -6x + 12 + 8

y = -6x + 20

Explain why the work is not correct.

Sagot :

wegnerkolmp2741o

Answer:

The student should subtract 8 from each side not add 8

Step-by-step explanation:

Point slope form is

y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line

y - -8 = -6(x -2)

y+8 = -6(x-2)

Distribute

y+8 = -6x+12

Subtract 8 from each side

y+8-8 = -6x+12-8

y = -6x+4

The student should subtract 8 from each side not add 8

Answer:

y -(-8) = -6(x - 2)

y -(-8) = -6x + 12

y -(-8) + 8 = -6x + 12 + 8 (this step is incorrect as minus into minus is plus therefore when taking 8 to the right hand side we must subtract it from the left hand side

y = -6x + 20

the correct equation would be : y= -6x+4

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