At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Answer:
Step-by-step explanation:
- Question 1) Take each point and move down two units. For example: Take point A, keeping it on the vertical line, and count two squares down, then place a new point there and call it A1. Do the same for each point in the parallelogram.
- Question 2) Take one point from parallelogram EFGH and move it two squares to the left. Then from that new point, count four squares down and place a new dot there. Do this for every point in the EFGH parallelogram.
- Question 3) This one is a bit trickier. Ok, so we know three points on the graph. L(-5, -5), M(-5, -2), and N(-2, -2). Ok so we know that if we plot these points, they will make three points in a square. All we need is the fourth point. To get that, we have to place all three points on the graph. Let's start with L. The coordinates are (-5, -5). Now, the first number is -5 which means to go 5 points to the left from the center point, then the next number is -5 again, so that means that from that point that we just made, you go 5 points down, and then that is your point L. Now, for point M, it is the same thing except for the second number, it tells us to go -2. So, instead of going 5 down like the first point, you must go 2 points down after you have to the left 5 points. REMEMBER: when plotting points, you always have o start in the center point(center of the graph). Negative numbers are always left and down. Positive numbers are always right and up. Do the same thing for point N (left 2, and then 2 down). After you have plotted all three of these points, you can see that there is one point missing. The point that we are missing is (-2, -5) (2 to the left, and 5 down).
- Question 4) Ok, so what you want to do is first plot your points. X(2, 1): start at center point and go 2 points to the right and one point up. Y(4,4): from center point, o 4 points to the right and the 4 points up. Z(5,2): from center point, go 5 points to the right then 2 points up. Now, connect your dots and it should make a triangle. Now for the tricky part. They want us to move our triangle 4 points down. So, start with letter Y and simply count 4 points down from its original point and place the new dot there. The new coordinates to this new Y point should be: (4, 0) (4 to the right of the center point and 0 up or down) So, this point should be on the line. The reason it is still 4 to the right is because all we did was move the point down and not left or right. DO this with the other two points and you should get: X(2, -3) (2 to the right and 3 down from center point) and Z(5, 2) (5 to the right and 2 down from center point)
- Question 5) THE FIRST NUMBER IS ALWAS THE NUMBER ON THE HORIZONTAL LINE.
I. the point is is moved 4 to the right of the center point and 2 down. So it is (4, -2)
P. This point is moved negative 4 (to the left) and down 3 . So it is: (-4, -3)
G. This point is moved 5 to the right and then up 2 which makes it (5, 2)
Q. This point is moved 6 to the right and 4 down which makes it (6, -4)
R. This point is moved 2 to the left and 2 up which makes it (-2, 2)
S. (6, 4)
J. (-2, -4)
U. (-5, 0)
H. (3, -1)
K. (-6, -5)
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.