Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

what is the average rate of change of y = cos (2x) on the interval [0, π2]?

Sagot :

fichoh

The average rate of change of the function y = cos(2x) over the interval (0, π/2) is [tex] \frac{-4}{\pi}[/tex]

The average rate of change over a given interval is defined thus :

  • [tex] R = \frac{f(b) - f(a)}{b - a}[/tex]

  • Where a and b are the interval values

At a = 0 :

  • f(0) = cos(2(0)) = Cos 0 = 1

At b = π/2 :

  • f(π/2) = cos(2(π/2)) = Cos π = - 1

Hence,

[tex] \frac{f(b) - f(a)}{b - a} = \frac{-1-1)}{\frac{\pi}{2} - 0} = \frac{-2}{\frac{\pi}{2}} = \frac{-4}{\pi} [/tex]

Therefore, the average rate of change over the interval is [tex] \frac{-4}{\pi}[/tex]

Learn more :https://brainly.com/question/7501987

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.