Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Write an equation in Slope-Intercept Form using the table below. ​

Write An Equation In SlopeIntercept Form Using The Table Below class=

Sagot :

Answer:

y = x + 46

Step-by-step explanation:

When writing an equation of a line, keep in mind that you always need the following information in order to determine the linear equation in slope-intercept form, y = mx + b:

1. 2 sets of ordered pairs (x, y)

2. Slope (m)

3. Y-intercept (b)

First, choose two pairs of coordinates to use for solving the slope of the line:

Let (x1, y1) = (0, 46)

(x2, y2) =  (1, 47)

User the following formula for slope

[tex]m = \frac{y2 - y1}{x2 - x1}[/tex]

Plug in the values of the coordinates into the formula:[tex]m = \frac{y2 - y1}{x2 - x1} = \frac{47 - 46}{1 - 0} = \frac{1}{1} = 1[/tex]

Therefore, the slope (m) = 1.

Next, we need the y-intercept, (b). The y-intercept is the y-coordinate of the point where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0. The y-coordinate of the point (0, 46) is the y-intercept. Therefore, b = 46.

Given the slope, m = 1, and y-intercept, b = 46, the linear equation in slope-intercept form is:

y = x + 46

Please mark my answers as the Brainliest if you find my explanations helpful :)