rileyxfox
Answered

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discipulus

Answer:

[tex] {( {x}^{ \frac{1}{4} } {y}^{16} )}^{ \frac{1}{2} } = {( {x}^{ \frac{1}{4}. \frac{1}{2} } {y}^{ \frac{16}{2} } )} \\ = {x}^{ \frac{1}{8} } {y}^{8} [/tex]

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