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Sagot :
Answer:
piecewise, continuous.
Step-by-step explanation:
This is piecewise simply because it is in pieces. Thus PIECEwise (Pun intended). This is continuous because, as you can see, there is a filled in dot on the same x coordinate as every empty dot. The empty dots mean that that value is not in that part of the graph. However, since the other parts of the function "fill the gaps," then it is continuous. I hope this helps!
It's offcourse piecewise
For continuity
Observe the graph
The domain is like
- (-oo,1]U(1,2]U(2,oo)
For close ineterval there is an open interval hence it's continuous
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