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bChoose the equation that represents the graph.

Oy = x - 3
Oy = -x + 3
Oy = -x-3
Oy = x + 3


BChoose The Equation That Represents The Graph Oy X 3 Oy X 3 Oy X3 Oy X 3 class=

Sagot :

The graph illustrates a linear function, because the graph is a straight line

The equation of the graph is (d) y = x +3

The points on the line are:

[tex](x_1,y_1) = (-3,0)[/tex]

[tex](x_2,y_2) = (0,3)[/tex]

First, we calculate the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Substitute values for x1, x2, y1 and y2

[tex]m = \frac{3-0}{0--3}[/tex]

Simplify

[tex]m = \frac{3}{3}[/tex]

Divide

[tex]m = 1[/tex]

The equation of the line is then calculated using the following formula:

[tex]y = m(x - x_1) + y_1[/tex]

Substitute values for m, x1 and y1

[tex]y = 1(x - -3) + 0[/tex]

Simplify

[tex]y = 1(x +3)[/tex]

Open bracket

[tex]y = x +3[/tex]

Hence, the equation of the graph is (d) y = x +3

Read more about linear graphs at:

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