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There are 40 runners in a race. How many ways can the runners finish​ first, second, and​ third?

Sagot :

jumpinggang6

Answer:

117600

Step-by-step explanation:

50 x 49 x 48 = 117,600 ways

You have 50 possible for 1st, 49 for 2nd, 48 for 3rd

or

Permutations 50P3 = 117,600

There are total 59280 ways that can the runners finish first, second and third in a race.

What is permutation?

A permutation is a mathematical technique that determines the number of possible arrangements in a set when the order of the arrangements matters.

Formula for permutation

[tex]nP_{r} =\frac{n!}{(n-r)!}[/tex]

Where,

[tex]nP_{r}[/tex] is permutation.

n is total number of objects.

r is number of objects selected.

According to the given question

Total number of runners, n = 40

Total number of runners to be selected for first, second and third position  is 3 i.e. r = 3

Therefore,

The number of ways can the runners finish the first, second and third is given by

[tex]40P_{3} = \frac{40!}{((40-3)!} =(40)(39)(38)=59280[/tex]

Hence, there are total 59280 ways that can the runners finish first, second and third in a race.

Learn more about Permutation here:

https://brainly.com/question/2295036

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