Answered

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solve for k.
k(4r−5)≥12r−9

Sagot :

rlesandisusanya

Answer:

[tex]k = \frac{12r - 9}{4r - 5} \\ [/tex]

Step-by-step explanation:

[tex]k(4r - 5) \geqslant 12r - 9 \\ k = \frac{12r - 9}{4r - 5} \\ [/tex]

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