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Find the surface area of a right cone that has a radius of 9 inches and a height of 12 inches. Round your answer to the nearest hundredth.​

Sagot :

Answer:

SA= 678.24 in^2

Step-by-step explanation:

SA = (pi)(r^2) + (pi)(r)(l)

r = radius

h = height

l = slant height

Pi = 3.14

Slant height:

l^2 = h^2 + r^2

l = sqrt (144+81)

= 15

SA = (pi)(9^2) + (pi) (9) (15)

SA = 254.34 + 423.9

SA= 678.24 square inches

If the slant height of the cone is 15 inches. Then the surface area of the cone will be 678.58 square inches.

How do find the surface area of some object?

Find the area that its outer surfaces possess. The Sum of all those surface areas is the surface area of the considered object.

If a right cone has a radius of 9 inches and a height of 12 inches.

Then the surface area of a right cone will be

The slant height is given as

l² = 9² + 12²

l² = 81 + 144

l² = 225

l = 15

Then the surface area will be

Surface area = πr² + πrl

Surface area = π x 9² + π x 9 x 15

Surface area = 81π + 135π

Surface area = 216π

Surface area = 678.58 square inches

Learn more about the surface area here:

https://brainly.com/question/15096475

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