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Sagot :
Convert the equation to the slope-intercept form.
[tex]4y-6x+12=0 \\ 4y=6x-12 \ \ \ |\div 4 \\ y=\frac{6}{4}x-\frac{12}{4} \\ y=\frac{3}{2}x-3[/tex]
In the [tex]y=mx+b[/tex] form, [tex]m[/tex] is the slope.
[tex]y=\frac{3}{2}x-3 \\ m=\frac{3}{2}=1\frac{1}{2}[/tex]
The slope is equal to [tex]1 \frac{1}{2}[/tex].
[tex]4y-6x+12=0 \\ 4y=6x-12 \ \ \ |\div 4 \\ y=\frac{6}{4}x-\frac{12}{4} \\ y=\frac{3}{2}x-3[/tex]
In the [tex]y=mx+b[/tex] form, [tex]m[/tex] is the slope.
[tex]y=\frac{3}{2}x-3 \\ m=\frac{3}{2}=1\frac{1}{2}[/tex]
The slope is equal to [tex]1 \frac{1}{2}[/tex].
[tex]4y-6x+12=0\\
4y=6x-12\\
y=\dfrac{6}{4}x-\dfrac{12}{4}\\
y=\dfrac{3}{2}x-3\\\\\\
m=\dfrac{3}{2}[/tex]
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