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How to solve 5x+8y=14 And 4x=24 by substitution

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[tex]5x+8y=14 \\ 4x=24 \\ \\ \hbox{solve the 2nd equation for x:} \\ 4x=24 \\ x=6 \\ \\ \hbox{substitute 6 for x in the 1st equation:} \\ 5 \times 6+8y=14 \\ 30+8y=14 \\ 8y=14-30 \\ 8y=-16 \\ y=-2 \\ \\ \hbox{the answer:} \\ x=6 \\ y=-2[/tex]
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