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Sagot :
[tex]5(2x-3)=3(x+4) \\
10x-15=3x+12 \\
10x-3x=12+15 \\
7x=27 \\
x=\frac{27}{7}=3 \frac{6}{7}[/tex]
[tex]5(2x-3) = 3(x+4)\\
10x-15=3x+12\\
7x=27\\
x=\dfrac{27}{7}[/tex]
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