Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
[tex]a,a+1,a+2,a+3-\ four\ consecutive\ integers\\\\
a+a+1+a+2+a+3=682\\\\
4a+6=682\ \ \ | subtract\ 6\\\\
4a=676\ \ \ | divide\ by\ 4\\\\
a=169\\\\
Number\ are\ 169,170,171,172.[/tex]
Because they're consecutive, it means that the first one is x, the second one is x+1, the third one is x+2 (x+1+1), and the fourth one is x+3. Because we're given that the sum of all of them is 682, just add all of them together:
x+(x+1)+(x+2)+(x+3)=682
x+x+x+x+1+2+3=682
4x+6=682
4x+6-6=682-6
4x=676
x=676/4
x=169
Thus, the consecutive integers are: 169, 170, 171, 172
x+(x+1)+(x+2)+(x+3)=682
x+x+x+x+1+2+3=682
4x+6=682
4x+6-6=682-6
4x=676
x=676/4
x=169
Thus, the consecutive integers are: 169, 170, 171, 172
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.