Answered

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logb121=2   
Can somebody help and explain?

Sagot :

madankapoor10
[tex]log_b 121=2 \\ log_b 11^2=2 \\ 2log_b11=2 \\ log_b11=1[/tex]
therefore b=11
[tex]log_b121=2\iff b^2=121\to b=\sqrt{121}\to b=11\\\\b > 0\ \wedge\ b\neq1\\\\\\\log_ab=c\iff a^c=b[/tex]
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