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Bobby's Christmas list had 3 more than twice as many items on it than Johnny's list. Jhonny asked for 8 fewer items than bobby. How many items were on Johnny's (x) and Bobby's (y) Christmas lists

Sagot :

because jonny asked for 8 fewer items than bobby and bobby's list had 3 more than twice that of johny, the "twice" is 5. Two possible answers for this problem could be 13 and 5 since they both satisfy the requirement. if you can't logically deduct a function for it, look at the problem closely, then test and guess! Have fun with math!

Answer:

Bobby made the Christmas list with 13 items, and Johnny with only 5 items.

Step-by-step explanation:

"Bobby's Christmas list hat 3 more than twice as many items than Johnny's". This statement is represented by:

[tex]B=2J+3[/tex]; where [tex]B[/tex] is Bobby, and [tex]J[/tex] is Johnny.

Then, the problem states, "Johnny asked for 8 fewer items than bobby", it's represented by:

[tex]J=B-8[/tex]

Now, to find the value of each variable, we solve this system of equations by substitution:

[tex]B=2J+3\\B=2(B-8)+3\\B=2B-16+3\\13=2B-B\\B=13[/tex]

Then, we replace this into second equation to find [tex]J[/tex]:

[tex]J=B-8=13-8=5[/tex]

Therefore, Bobby made the Christmas list with 13 items, and Johnny with only 5 items.

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