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Sagot :
3(4x-2) expanded
12x-6
2(6x-3) expanded
12x-6
12x-6=12x-6
They both cancel each other out
Whatever x is it will be correct. As long as it is the same in both parts of the equation.
This makes it impossible to give a number as to how many solutions it has.
12x-6
2(6x-3) expanded
12x-6
12x-6=12x-6
They both cancel each other out
Whatever x is it will be correct. As long as it is the same in both parts of the equation.
This makes it impossible to give a number as to how many solutions it has.
[tex]3(4x-2)=2(6x-3) \\
12x-6=12x-6 \\
12x-12x=-6+6 \\
0=0[/tex]
0 is always equal to 0 no matter what x is, so the equation is true for all values of x.
The equation has infinitely many solutions.
0 is always equal to 0 no matter what x is, so the equation is true for all values of x.
The equation has infinitely many solutions.
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