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if (x+2) is a factor of x^3-6x^2+kx+10, k=

Sagot :

konrad509
If a binomial [tex](x-a)[/tex] is a factor of a polynomial, then [tex]a[/tex] is a root of this polynomial.

[tex](x+2)=(x-(-2)) \Rightarrow a=-2\\\\ (-2)^3-6\cdot(-2)^2+k\cdot(-2)+10=0\\ -8-24-2k+10=0\\ -2k=22\\\ \boxed{k=-11} [/tex]

skydreammer50923

Answer:

k=-11

Step-by-step explanation:

for plato

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