Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

What is the equation in slope-intercept form of the line
that crosses the x-axis at 3 and is perpendicular to y= 3/4x-5

Sagot :

Answer:

y = (-4/3)x + 4  

Step-by-step explanation:

Let y = mx + b, be the equation of the line in slope intercept form where we need to find m and b.

Perpendicular to y = (3/4)x - 5, means that m = - (1 / (3/4) ) = - 4/3

So, at this point, y = (-4/3)x + b.

Crossing the x - axis at 3 means that (3, 0) is a point on the line, where we note that x=3 and y=0.

Thus, we plug in these values into the equation y = (-4/3)x + b, to get

0 = (-4/3)(3) + b

0 = -4 + b, so that

b = 4.

Hence, the answer is:

y = (-4/3)x + 4

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.