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What is the equation in slope-intercept form of the line
that crosses the x-axis at 3 and is perpendicular to y= 3/4x-5


Sagot :

Answer:

y = (-4/3)x + 4  

Step-by-step explanation:

Let y = mx + b, be the equation of the line in slope intercept form where we need to find m and b.

Perpendicular to y = (3/4)x - 5, means that m = - (1 / (3/4) ) = - 4/3

So, at this point, y = (-4/3)x + b.

Crossing the x - axis at 3 means that (3, 0) is a point on the line, where we note that x=3 and y=0.

Thus, we plug in these values into the equation y = (-4/3)x + b, to get

0 = (-4/3)(3) + b

0 = -4 + b, so that

b = 4.

Hence, the answer is:

y = (-4/3)x + 4