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Micah is at a donut shop and wants to choose his own dozen. There are ample glazed,
chocolate and jelly donuts. If Micah wants at least two jelly donuts, how many different
combinations of donuts can Micah use to create a box of a dozen donuts?


Sagot :

Answer:

Well lets label them

There are 4 choices

And the 4 choices can make up a dozen

He wants at least 2 jelly donuts

So instead of drawing over a 100 different combinations of donuts and checking them we can Do it like this

Well we know there has to be at least 2 jelly donuts out of the dozen so at least 2 of the donuts are jelly. Now you have 10 donut spaces left

So 1/4*1/4*1/4*1/4 since 4 options is 1/288 Now you have 1/288.

So 288 spaces? I’m not sure haven’t done this in a while just search up probability calcualtions