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To what volume should 1 L of a solution of a weak acid HA be diluted to reduce the H+] to one-half of that in the original solution?
Express your answer using one significant figure.

Sagot :

Eduard22sly

The solution should be diluted to 2 L to reduce the concentration of the hydrogen ion, [H+] to one-half of that in the original solution.

Let the original molarity of the solution be 1 M

Thus,

The molarity of the diluted solution = 1 × ½ = 0.5 M

  • Finally, we shall determine the volume of the diluted solution. This can be obtained as follow:

Volume of stock solution (V₁) = 1 L

Molarity of stock solution (M₁) = 1 M

Molarity of diluted solution (M₂) = 0.5 M

Volume of diluted solution (V₂) =?

M₁V₁ = M₂V₂

1 × 1 = 0.5 × V₂

1 = 0.5 × V₂

Divide both side by 0.5

V₂ = 1 / 0.5

V₂ = 2 L

Therefore, the solution should be diluted to 2 L to reduce the concentration of the hydrogen ion, [H+] to one-half of that in the original solution.

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