Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A pendulum bob is displaced from equilibrium and held where its height is
h = 14.6cm above its equilibrium position. If the bob is released, how fast will it be moving when it crosses the lowest point of its swing?


Sagot :

Answer:

Explanation:

the gravity potential energy will convert to kinetic energy in the absence of friction.

½mv² = mgh

v = √(2gh)

v = √(2(9.81)(0.146))

v = 1.69 m/s

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.