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Sagot :
Slope:-
[tex]\\ \sf\longmapsto \dfrac{4-8}{2-4}=\dfrac{-4}{-2}=2[/tex]
Equation
- y=2x
As equation B is greater than Equation A so
- y=3x
Option C is correct
Answer:
(4 , 8 ) (2,4)
In the equation,
y = mx + c
m => slope
c => y intercept
First, Let us find the slope
[tex]m = \frac{y1 - y2}{x1 - x2} \\ m = \frac{8 - 4}{4 - 2} \\ m = \frac{4}{2} \\ m = 2[/tex]
Now let's find the y intercept
[tex](4 \: \: 8) \\ y = mx + c \\8 = 2 \times 4 + c \\ 8 = 8 + c \\ 8 - 8 = c \\ 0 = c[/tex]
So, the equation of the line A is,
y = mx + c
y = 2x + 0
y = 2x
As the relationship B is greater than the relationship A
The answers should be,
[tex]y = 2.2x \: \\ or \\ y = 3x[/tex]
Hope this helps you.
Let me know if you have any other questions :-):-)
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